-16t^2+63t+4=50

Solution for -16t^2+63t+4=50 equation:

-16t^2+63t+4=50

We move all terms to the left:

-16t^2+63t+4-(50)=0

We add all the numbers together, and all the variables

-16t^2+63t-46=0

a = -16; b = 63; c = -46;
Δ = b2-4ac
Δ = 632-4·(-16)·(-46)
Δ = 1025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1025}=\sqrt{25*41}=\sqrt{25}*\sqrt{41}=5\sqrt{41}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-5\sqrt{41}}{2*-16}=\frac{-63-5\sqrt{41}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+5\sqrt{41}}{2*-16}=\frac{-63+5\sqrt{41}}{-32}
$